3(1-y)^2+5(1-y)=-2

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Solution for 3(1-y)^2+5(1-y)=-2 equation: 



3(1-y)^2+5(1-y)=-2

We move all terms to the left:

3(1-y)^2+5(1-y)-(-2)=0

We add all the numbers together, and all the variables

3(-1y+1)^2+5(-1y+1)-(-2)=0

We add all the numbers together, and all the variables

3(-1y+1)^2+5(-1y+1)+2=0

We multiply parentheses

3(-1y+1)^2-5y+5+2=0

We add all the numbers together, and all the variables

-5y+3(-1y+1)^2+7=0

We move all terms containing y to the left, all other terms to the right

-5y+3(-1y+1)^2=-7

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